Question 869910
Solve each equation and inequality. Use set-builder or interval notation to write solution sets to the inequalities. 
(a) x^2 - x - 12 = 0
(x-4)(x+3)=0
x=4
or
x=3
..
(b) x^2 - x - 12 < 0
(x-4)(x+3)<0
number line:
<.....+....-3....-.....4....+....>
solution: (-3, 4)
..
(c) x^2 - x - 12 >0
(x-4)(x+3)>0
number line:
<.....+....-3....-.....4....+....>
solution: (-&#8734;,-3) U (4,&#8734;)