Question 869901
Perpendicular lines have slopes that are negative reciprocals.
{{{m[1]*m[2]=-1}}}
{{{(3/4)*m[2]=-1}}}
{{{m[2]=-4/3}}}
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{{{y=-(4/3)x+b}}}
Use the point to solve for {{{b}}}
{{{9=-(4/3)(-2)+b}}}
{{{27/3=8/3+b}}}
{{{b=19/3}}}
{{{highlight(y=-(4/3)x+19/3)}}}