Question 869874
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Hi
ln(1) = n
e^n = 1
 n = 0
*[tex \large\ \ log_b(x) \ = \ y \ \ \Rightarrow\ \ b^y = x] Applied
*[tex \large\ \ nlog_bx = log_b(x^n) ]
*[tex \large\ \ log_bx + log_by = log_b(xy) ]
*[tex \large\ \ log_bx - log_by = log_b(x/y) ]
*[tex \large\ \ log_b1 = 0]  
*[tex \large\ \ log_bb = 1] 
*[tex \large\ \ ln e^x = x]
{{{ e^(lnx) = x}}}