Question 869869
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Hi
{{{(y+2)^2/3^2-(x-1)^2/4^2=1}}}
center:  (1,-2)
vertices(b=3):  (1,1) and (1,-5)
foci: |sqrt(9+16)| = 5,  F(1,3) and (1, -7)
Standard Form of an Equation of an Hyperbola opening up and down is:
  {{{(y-k)^2/b^2 - (x-h)^2/a^2 = 1}}} with C(h,k) and vertices 'b' units up and down from center,
Foci {{{sqrt(a^2+b^2)}}}units units up and down from center, along x = h