Question 869838
{{{sqrt(-36)/(2-3i+3+2i)=(6i)/(5-i)}}}
{{{sqrt(-36)/(2-3i+3+2i)=((6i)/(5-i))((5+i)/(5+i))}}}
{{{sqrt(-36)/(2-3i+3+2i)=(30i+6i^2)/(25-5i+5i-i^2)}}}
{{{sqrt(-36)/(2-3i+3+2i)=(-6+30i)/(26)}}}
{{{sqrt(-36)/(2-3i+3+2i)=(-3+15i)/(13)}}}