Question 869658
{{{3x+ 5y = 15}}}
{{{3x - 6y = -12}}}
Subtract one equation from the other,
{{{3x+5y-3x+6y=15+12}}}
{{{11y=27}}}
{{{y=27/11}}}
Then use either equation to solve for {{{x}}}.
{{{3x+5(27/11)=165/11}}}
{{{3x=(165-135)/11}}}
{{{3x=30/11}}}
{{{x=10/11}}}