Question 869772
Factor 

128x^6 - 2y^6

So far I have factored a 2 out leaving me with 2(64x^6-y^6)
I am confused where to go from here, I believe im supposed to set it up as a difference of squares or cubes, but im not sure how to go about that.
<pre>
{{{128x^6 - 2y^6}}}
{{{2(64x^6 - y^6)}}}
{{{2((8x^3)^2 - (y^3)^2)}}}
{{{2(8x^3 - y^3)(8x^3 + y^3)}}}
{{{2((2x)^3 - (y)^3)((2x)^3 + (y)^3)}}}
{{{2((2x - y)((2x)^2 + 2xy + y^2))((2x + y)((2x)^2 - 2xy + y^2))}}}
{{{highlight_green(2((2x - y)(4x^2 + 2xy + y^2)(2x + y)(4x^2 - 2xy + y^2)))}}}