Question 869725
Circles are of the form {{{(x-h)^2+(y-k)^2=r^2}}} with center (h,k) and radius r.



We're given "center (-3,7) and radius is 12", so (h,k) = (-3,7) ----> h = -3, k = 7 and r = 12



Plug these values in:



{{{(x-h)^2+(y-k)^2=r^2}}}



{{{(x-(-3))^2+(y-7)^2=12^2}}}



{{{(x+3)^2+(y-7)^2=144}}}



and that's your final answer