Question 869410
{{{log(2,(y+6))+log(2,(y-1))=1+log(2,(3y))}}}
{{{log(2,((y+6)(y-1))/(3y))=1}}}
{{{((y+6)(y-1))/(3y)=2}}}
{{{((y+6)(y-1))=6y}}}
{{{y^2-y+6y-6=6y}}}
{{{y^2-y-6=0}}}
{{{(y-3)(y+2)=0}}}
Two solutions:
{{{y-3=0}}}
{{{y=3}}}
and
{{{y+2=0}}}
{{{y=-2}}}
The second solution would not work since {{{log(2,(-3))}}} and {{{log(2,(-6))}}}
are not defined.