Question 869529
Perpendicular lines have slopes that are negative reciprocals.
{{{6*m=-1}}}
{{{m=-1/6}}}
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{{{y-(-7)=-(1/6)(x-15)}}}
{{{y+7=-(1/6)x+5/2}}}
{{{y=-(1/6)x+5/2-14/2}}}
{{{y=-(1/6)x-9/2}}}

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{{{drawing(300,300,-5,15,-10,10,grid(1),circle(15,-7,0.3),graph(300,300,-5,15,-10,10,6x-10,-(1/6)x-9/2))}}}