Question 869476
{{{ln((x+4)*(x+1)) = 2ln(x+3)}}}
{{{ln((x+4)*(x+1)) = ln((x+3)^2)}}}
so {{{(x+4)*(x+1) = (x+3)^2}}}
{{{x^2 +5x + 4 = x^2 + 6x + 9 }}}
add {{{-x^2}}} to each side
{{{5x + 4 = 6x + 9 }}}
add -5x to each side
 4 = x + 9
add -9 to each side
 -5 = x

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http://www.wolframalpha.com/input/?i=ln%28x%2B4%29%2Bln%28x%2B1%29%3D2ln%28x%2B3%29