Question 869457
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Hi
7, 8, 9, 10, 11, 12, 13
choose two:
7C2 = 21 in the sample space (assuming Order is not important)
2 Even Sample Space: (8,10),(8,12) (10,12)
P(2 Even) = 3/21 = 1/7
two Odd Sample Space: (7,9), (7,11),(7,13),(9,11), (9,13), (11,13)
P(2 Odd) = 6/21 = 2/7
P(Even and Odd) = 1 - 1/7 - 2/7 = 4/7