Question 73158
Just plug in -2 for x
{{{f(-2)=5(-2)^2-3(-2)+1}}}
{{{f(-2)=5(4)+6+1}}}
{{{f(-2)=5(4)+6+1}}}
{{{f(-2)=27}}}
In this case you're not solving for x, it's already given as x=-2. You're actually solving for f(x).