Question 869314
Which, min or max?


You first learn about {{{y=x^2}}}, which has a minimum.  If change sign to {{{y=-x^2}}}, then this has a maximum.  Now you know.


Vertex?  F(x) is not factorable, so find vertex in either of two ways.  General solution, or complete the square.  


{{{-1(x^2+2x+6)}}}
{{{-1(x^2+2x+1-1+6)}}}
{{{-1((x+1)^2+5)}}}
{{{highlight(-(x+1)^2-5)}}}


The maximum is the vertex which you read directly from this standard form expression.  Point (-1,-5).