Question 869302
Since (f - g)(2) = f(2) - g(2), we need the individual values of f(2) and g(2):


f(x) = 2x + 4
f(2) = 2(2) + 4 ... plug in x = 2 and evaluate
f(2) = 8


--------------


g(x) = 3x - 5
g(2) = 3(2) - 5 ... plug in x = 2 and evaluate
g(2) = 1


-------------


So,


(f - g)(2) = f(2) - g(2)
(f - g)(2) = 8 - 1
(f - g)(2) = <font color="red">7</font>