Question 869183
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Hi
{{{(25)^(10x+8)=(1/25)^(4-2x) }}}
{{{(25)^(10x+8)=(25^(-1))^(4-2x)) }}}
{{{(25)^(10x+8)=(25)^(2x-4) }}}
    10x +8 = 2x - 4
    8x = -12
     x = -12/8 =  -1.5