Question 868984
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Re TY, Yes, statistically (and in life), expected value(profit) can be a negative number.
Had .1% in my head somehow
My thoughts...using .01
 p(success) = .01 0r 1%
 a) E = {{{.01*100*5 -.99*99*5 }}} = -485.05€ More politically correct (on the win: net 5€)
 b) m = np 0r p = m/n , .01 = 1/100, n = 100, m = 1
On an average 100 boxes to win one (Cost for the Boxes 500€ ):  Net cost: 490€(with a win) 
 c)P(X &#8805; 1) = 1 - binomcdf(69, .01, 0) = .5002, min 69
 d) P = 1C1(.01)^1(.999)^0 = .01 
 e)average 1/100 weeks P(x = 2) = .1839 Poisson (average: 1)
 f) P(x = 0) = .3679 Poisson (average:1)