Question 869023
For inverse variation and those two points, you would expect 5 varies inversely with 9, so say {{{highlight_green(9=k/5)}}}.  The value of {{{k=9*5}}}.


The unknown point (x, 6) fits the model as {{{6=k/x}}}.
{{{x/k=1/6}}}
{{{x=k/6}}}
{{{x=(9*5)/6=(3*5)/2}}}
{{{highlight(x=7&1/2)}}}