Question 868825
Q:
{{{(5/y + 3)^2 + 3(5/y+3)=10 }}}
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A:
Let x = {{{(5/y  +  3)}}}
The original equation becomes
{{{x^2 + 3x = 10}}}
{{{x^2 + 3x - 10 = 0}}}
Factor the left side.
(x + 5)(x - 2) = 0
x = -5, 2
Therefore, {{{5/y  +  3 = -5}}} or {{{5/y  +  3 = 2}}}
{{{5/y  =  -8}}} or {{{5/y  =  -1}}}
Answer: y = {{{highlight(-5/8)}}} or {{{highlight(-5)}}}