Question 868808
solve (3^2x) -[5(3^x)]=-6
(3^2x) + 6 = 5*3^x
------------
You can't say 
log(3^2x) + log(6) = log(5*3^x)
The log of a sum is not the sum of the logs.
That's where you went wrong.
------------
(3^2x) -[5(3^x)]=-6
(3^2x) - 5(3^x) + 6 = 0
That cannot be solved by algebraic methods.
You can use a graphing calculator or iterative methods.
1 is a zero.
0.63092975357146 is the second zero.