Question 868717
I need help in figuring out how to graph the following function: 
f(x)=square root of x+2 and to find the domain, range and to find the interval on which f is increasing, is decreasing, or is constant 
Here's what I did: 
I set up a table and I used 1,2,3,4 as the value of x. Then I plugged those values into the function to get the values for f(x) and got: 
for x=1 -- I got f(x)= square root of 3 or 1.7 --- (square root of 1+2 = square root of 3)
for x=2 -- I got f(x)= square root of 4 or 2 --- (square root of 2+2 = square root of 4)
for x=3 -- I got f(x)= square root of 5 or 2.2 --- (square root of 3+2 = square root of 5)
for x=4 -- I got f(x)= square root of 6 or 2.4 --- (square root of 4+2 = square root of 6) 
Then I plotted my graph based on those points with a range of [1.7, infinity)
and a domain of [1, infinity). The text says that my graph, range and domain are incorrect. The text says that the domain is [-2, infinity) and the range is [0, infinity). I need to know how they got that domain and range and how to plot the points for the graph.
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f(x) = sqrt(x+2)
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Domain ?
Solve x+2 >= 0
x >= -2
That is the Domain
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Range:: [0,+oo)
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Graph::
{{{graph(400,400,-5,20,-5,20,sqrt(x+2))}}}
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Cheers,
Stan H.
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