Question 868711
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Hi
x^2 -4x + 4y^2 + 8y
{{{(x-2)^2 + 4(y+1)^2 = 8}}}
{{{(x-2)^2/8 + (y+1)^2/2 = 1}}}
C(2,-1)
sqrt(8-2) = &#8730;6
Foci are: (2-&#8730;6, -1) and (2+&#8730;6, -1)