Question 868569
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Hi
 x^2 + 2x = 8
 x^2 + 2x - 8 = 0
 (x + 4)(x-2) = , x = -4, 2
*[tex \large\ \ log_b(x) \ = \ y \ \ \Rightarrow\ \ b^y = x]  Applied
*[tex \large\ \ nlog_bx = log_b(x^n) ]
*[tex \large\ \ log_bx + log_by = log_b(xy) ]
*[tex \large\ \ log_bx - log_by = log_b(x/y) ]
*[tex \large\ \ log_b1 = 0]
*[tex \large\ \ log_bb = 1]