Question 868503
When it crosses the x-axis, {{{y=0}}}
{{{2(0)=x-4}}}
{{{x-4=0}}}
{{{x=4}}}
(4,0)
First, find the slope.
{{{m=(y[2]-y[1])/(x[2]-x[1])=(10-0)/(-1-4)=(10/(-5))=-2}}}
Use the point slope form with either point,
{{{y-0=-2(x-4)}}}
{{{y=-2x+8}}}
.
.
.
{{{drawing(300,300,-2,12,-2,12,grid(1),
circle(4,0,0.32),
circle(-1,10,0.32),
graph(300,300,-2,12,-2,12,(x-4)/2,-2x+8))}}}
.
.
{{{2y=x-4}}} Red line
{{{y=-2x+8}}} Green line