Question 868461
If, log 'e' 2 * log 'b' 625 = log '10' 16 * log 'e' 10. What is b?
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log(2)/log(e) + log(625)/log(b) = log(16)/log(10) + log(10)/log(e)
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ln(2)-ln(10) = log10(16)- logb(625)
ln(1/5) = ln(16)/ln(10) - ln(625)/ln(b)
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-1.609 = 1.204 - [ln(625)/ln(b)]
2.813 = 6.438/ln(b)
ln(b) = 2.289
b = 9.862
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Cheers,
Stan H.
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