Question 868250
<pre><font face = "consolas" color = "indigo" size = 3><b>
Hi
*[tex \large\ \ log_b(x) \ = \ y \ \ \Rightarrow\ \ b^y = x]
*[tex \large\ \ nlog_bx = log_b(x^n) ]
*[tex \large\ \ log_bx + log_by = log_b(xy) ]
*[tex \large\ \ log_bx - log_by = log_b(x/y) ]
*[tex \large\ \ log_b1 = 0]
*[tex \large\ \ log_bb = 1]
{{{log(10, 3x/4(x-1)) = 0}}}
    {{{3x/4(x-1) = 1}}}
      3x = 4x-4
      -x = -4,   x = 4
A=P{1+r/n}^nt 
A = Accumulated Amount
P= principal = 
r= annual rate = .
n= periods per year = 
t= years =
A = 2500(1+ .105/12)^48
A = 2500(1.00875)^48 = $3,797.96