Question 867523
{{{(x-4)^2+y^2=10}}}
{{{x^2+(y-20)^2=225}}}
These are both circles. 
The first one is centered at ({{{4}}},{{{0.0}}}) and has a radius of {{{sqrt(10)}}}
The second one is centered at ({{{0.0}}},{{{20}}}) and has a radius of {{{15}}}.
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{{{drawing(300,300,-30,30,-30,30,grid(1),circle(4,0,sqrt(10)),circle(0,20,15))}}}
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Since the circles don't intersect, there is no solution to the system of equations.