Question 867491
Find an equation for the parabola that has its vertex at the origin and satisfies the given condition(s). 
Focus: F(0,2) 
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Given data shows that parabola opens upwards with vertex at (0,0)
Its basic form of equation: x^2=4py
For given parabola: 
vertex: (0,0)
axis of symmetry:x=0 or y-axis
p=2 (distance from vertex to focus on the axis of symmetry
4p=8
Equation of given parabola: x^2=8y