Question 867758
Write the equation of the parabola with the shape as f(x)=-2x^2, but with the vertex (-3,2) 
Find the vertex of the graph f(x)=3x^2-12x+5 and determine whether the graph opens upward or downward
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f(x)=-2x^2
Parabola with same shape with vertex at (-3,2):
f(x)=-2(x+3)^2+2
...
f(x)=3x^2-12x+5
complete the square:
f(x)=3(x^2-4x+4)+5
f(x)=3(x-2)^2+5
coefficient, 3>0
so, parabola opens upward