Question 867750
I'm guessing that "underroot" means square root. Of so then equation is:
{{{-x^2-sqrt(3) = 0}}}<br>
And if this is the equation then we can tell by examination that the equation has no roots/solutions.<br>
No matter what value x has, the {{{-x^2}}} is either negative or zero. The square root of 3 is positive. And when you subtract a positive from a negative (or from zero), as indicated by {{{-x^2-sqrt(3)}}}, there is no way for the expression to end up with a value of zero. {{{-x^2-sqrt(3)}}} can only have a negative value, no matter what value x has.<br>
P.S. You did not mention complex roots. So I assumed that you were only interested in real roots (of which there are none).If you do want complex roots, then simply use the quadratic formula on {{{-x^2-sqrt(3) = 0}}} (with an "a" of -1, a "b" of zero and a "c" of {{{-sqrt(3)}}}).