Question 867545
{{{px^2 - ( 2p + q) x + p + q = 0}}}


here a = p, b= -(2p+q), c= (p+q)

Use formula method

{{{x=(-b+-sqrt(b^2-4ac))/(2a)}}}


{{{b^2-4ac = (-(2p+q))^2- 4*p*(p+q)}}}

={{{4p^2+4pq+q^2-4p^2-4pq}}}

={{{q^2}}}

{{{x=((2p+q)+-sqrt(q^2))/(2p)}}}

solve 

x1= (2p+q+q)/2p

=(p+q)/p

x2= (2p+q-q)/2p

=1