Question 867492
Find, with 95 percent confidence, the number of such students that should be randomly sampled if we want the margin of sampling error to be no more than three percentage points.
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Since E = z*s/sqrt(n), 
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n = [z*s/E]^2
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Your Problem:
n = [[1.96*s/0.03]^2
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Note:: The standard deviation is missing from your post
so "n" cannot be calculated.
Cheers,
Stan H.
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