Question 867475
If log[5]2=x, show that log[2]=x/x+1.
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{{{x = log(5,2)}}}
{{{x+1 = log(5,2) + log(5,5) = log(5,10)}}}
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{{{x/(x+1) = log(5,2)/log(5,10)}}}
= {{{(log(2)/log(5))/(log(10)/log(5))}}}
= log(2)/log(10) = log(2)/1
= log(2)