Question 867515
4^(6+x)=(1/2)^(7-x)
Whenever you see variables in exponents, it usually is a good idea to solve problem with logarithms.
(6+x) log4=(7-x)log(1/2)
(6+x)/(7-x)=log(1/2)/log4
(6+x)/(7-x)=-0.5
6+x=-.5(7-x)
6+x=-3.5+.5x
.5x=-9.5
x=-19