Question 867320
An actor invests some money at 8%, and $38000 more than three times the amount at 11%. The total annual interest earned form the investment is $34101. How much did he invest at each amount?
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let x=amt of money invested at 11%
3x+38000=amt of money invested at 8%

.11x+.08(3x+38000)=34101
.11x+.24x+3040=34101
0.35x=31061
x=≈88746
3x+38000≈304237
amt of money invested at 11%≈$88,746
amt of money invested at 8%≈$304,238