Question 867342
Suppose the 3-digit number is abc.


a is prime, and two digits are squares --> b, c are squares (in particular, c = 9 or c = 1).


If c = 1, then b = 0 (since c > b), but this implies a = 0, which doesn't work.


If c = 9, then b = 4 or 1. b cannot be 1 since b = 2a, so b = 4, and a = 2.


# = 249