Question 867265
a)
log(base 2)(x + 1)+ log(base 2)(x-1) = 3
2^log(base 2)(x + 1)*2^log(base 2)(x-1)=2^3
(x+1)(x-1)=8
x^2=9
x=3
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b)
log(base 2)(x^2-1) = 3
2^log(base 2)(x^2-1) =2^3
x^2-1=8
x^2=9
x=3, x=-3
.
c) x can't equal -1 in a) because a log cannot equal 0 or be negative.
.
Ed