Question 866774
{{{x^2+7x+12= (x+4)(x+3) }}}
{{{10x^2+18x-4= 2(5x^2+9x-2)=2(5x-1)(x+2) }}}
{{{x^2+9x+20= (x+5)(x+4) }}}
{{{5x^2+24x-5= (5x-1)(x+5) }}}
Remember, dividing by a fraction is the same as multiplying by its reciprocal.
{{{((x^2+7x+12)/(10x^2+18x-4)) / ((x^2+9x+20)/(5x^2+24x-5))=((x^2+7x+12)/(10x^2+18x-4))*((5x^2+24x-5)/(x^2+9x+20))}}}
{{{((x^2+7x+12)/(10x^2+18x-4)) / ((x^2+9x+20)/(5x^2+24x-5))=(((x+4)(x+3))/(2(5x-1)(x+2)))*(((5x-1)(x+5))/((x+5)(x+4)))}}}
{{{((x^2+7x+12)/(10x^2+18x-4)) / ((x^2+9x+20)/(5x^2+24x-5))=(x+3)/(2(x+2))}}}