Question 867099

Please help me! I am so confused on this, I have tried it several times but its just not clicking tonight.. The question is. 
 
The area of a right triangle is 260 in^2 
Find the length of its legs if one leg is 6 inches longer than the other. (Use the five step method and show ALL work for full credit.) 
 
 
If you could please explain this when helping me with this problem so I can solve the other problems similar to this one on my own. Thank you!
<pre>
Let longer leg be L
Then shorter leg = L - 6
Therefore, {{{(1/2)L(L - 6) = 260}}}
{{{(L^2 - 6L)/2 = 260}}}
{{{L^2 - 6L = 520}}} ------- Cross-multiplying
{{{L^2 - 6L - 520 = 0}}}
Solve for L, the longer leg, and then the shorter leg, or L - 6
You then do a check!! 

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