Question 73016
There are 4 twos in a deck of 52 cards.  So the chance that the first card is a two is 4 in 52
which is the same as 4 divided by 52 and this is a probability of 0.076923076.
.
Once the first card is dealt, there are 51 cards remaining in the deck.  In that group there
are 4 tens.  So the chances of drawing a 10 are 4 in 51 which is the same as 4 divided by 
51 and this is 0.078431372.
.
The chance of drawing first a two and then a ten is the product of these two probabilities
and this is:
.
(0.076923076)*(0.078431372) = 0.006033182389
.
that's your answer.  You can round it off. It translates that if you tried this dealing
(two cards from a deck of 52 without putting the card back that you drew first) a thousand times 
the odds are that you would first draw a two and then a ten about 6 times.
.
Hope this helps you to see how to do this problem.