Question 73016
Probability that the first card is a two: There are 4 two cards out of 52
P(card of two)=4/52=1/13
Probability that the second card is a ten: There are 4 ten cards out of 51 (take one 2 out of the deck)
P(card of ten)=4/51
Now since these two events need to happen at once, we multiply the two probabilities
P(two and a ten)=P(card of two)*P(card of ten)=(1/13)*(4/51)=4/663
So the chances of drawing a 2 and then a ten is 4/663 or 0.00603 (a 0.6% chance)