Question 866962
Law of Sines question, is there a triangle that satisfies a = 4, b = 8, and alpha = 64 degrees? 
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sin(B)/b = sin(A)/a
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sin(B) = 8[sin(64)/4] = 2*sin(64) = 1.84
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But, no angle has a sin greater than "1".
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Ans: No such triangle.
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Cheers,
Stan H.
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