Question 866887

{{{ x^2-11x+24=0}}}... factor completely and find the roots; write {{{-11x}}} as {{{-8x-3x}}} 

{{{x^2-8x-3x+24=0}}}......group

{{{(x^2-8x)-(3x-24)=0}}} ......factor

{{{x(x-8)-3(x-8)=0}}}

{{{(x-3)(x-8)=0}}}

solutions

if {{{x-3=0}}}=> {{{x=3}}}

if {{{x-8=0}}}=> {{{x=8}}}

so, the dimensions of a rectangle are: the length is {{{8}}} and the width is {{{3}}}