Question 866860
There are 36 possible outcomes for a pair of dice. 
There are 5 possible outcomes that sum to 6 : (1,5) (2,4) (3,3) (4,2) (5,1)
There are 11 possible outcomes with at least one 4:(1,4) (2,4) (3,4) (4,1) (4,2) (4,3) (4,4) (4,5) (4,6) (5,4) (6,4)
There are 2 possible outcomes that are in both lists: (2,4) (4,2)
{{{P(A_or_B)=5/36+11/36-2/36}}}
{{{P(A_or_B)=14/36=7/18}}}