Question 866737
{{{2 (x^2 + 1) = 5x}}}
{{{2x^2+2=5x}}}
{{{2x^2-5x+2=0}}}
{{{(x-2)(2x-1)=0}}}
Two solutions:
{{{x-2=0}}}
{{{x=2}}}
and
{{{2x-1=0}}}
{{{2x=1}}}
{{{x=1/2}}}