Question 866756
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Hi,
<img src='http://img210.imageshack.us/img210/7630/pyramid.png' border='0'/></a>
Surface Area: Add the area of the base to the sum of the areas of all of the triangular faces. 
h = 14ft
Area[Base] = 36ft^2
Area[Triangular face]= (1/2)(6ft)(s)  where s is slant height = {{{sqrt(14^2 + 3^2) = sqrt(205)}}}
{{{S[Area] = 36f^2 + 4(3sqrt(205))ft^2 = 36ft^2 + 12sqrt(205)ft^2}}}