Question 866650
This is a binomial distribution problem with p = 1/6 (that's the probability of rolling a single 3), n = 12



In this case, x = 3 since we want exactly 3 threes.



Now compute n C x = 12 C 3 = (12!)/(3!*(12-3)!) = 220. This is the binomial coefficient.



So we'll then have 220*p^(x)*(1-p)^(n-x) = 220*(1/6)^(3)*(1-1/6)^(12-3) = 0.19739571242092



So the probability of getting exactly 3 threes is approximately <font color="red">0.19739571242092</font> (roughly 19.73957%)