Question 866409
If sin[theta]= 3/8 
what does sec[theta]+tan[theta] equal? 
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use x for theta:
sinx=3/8
cosx=√(1-sin^2x)=√(1-9/64)=√(55/64)=√55/8
secx=1/cosx=8/√55
tanx=sinx/cosx=3/√55
secx+tanx=(8/√55)+(3/√55)=11/√55