Question 866322
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Hi
mean of 318 mg of sodium, and the standard deviation is 32 mg.
n = 60 
a) SE = 32/sqrt(60)= 4.1312
b) ME = 1.96(4.1312) = 8 
CI: 318-8 < u < 318 + 8   (310, 336)
c) .7(465) = 325.5, Yes reduced. It is in the confidence Interval

CI	z -value
90%	z =1.645
92%	z = 1.751
95%	z = 1.96
98%	z = 2.326
99%	z = 2.576