Question 866321
The sequence of numbers divisible by 4, with a remainder of 1 are 5,9,13,17,21,...
The general formula for the nth term of this sequence is a_n = 4n + 1
The sum of the first n terms of an arithmetic sequence, S_n = (n/2)*(a_1 + a_n)
n=24 gives the largest two digit number, 97.

S_24 = (24/2)(5+97) = 1224.  But the two digit numbers start with 13, so we need to subtract 5+9=14 from this sum
Ans: 1210